Found inside – Page 518Some writers call Emr2 = ? url = g the moment of inertia . ... For a sphere suspended by a cord , r = radius , h distance of axis of motion from the center of the sphere , ' h ' . distance of center of oscillation from center of sphere ... For that we use; ⇒ Check Other Object’s Moment of Inertia: NCERT Solutions Class 12 Business Studies, NCERT Solutions Class 12 Accountancy Part 1, NCERT Solutions Class 12 Accountancy Part 2, NCERT Solutions Class 11 Business Studies, NCERT Solutions for Class 10 Social Science, NCERT Solutions for Class 10 Maths Chapter 1, NCERT Solutions for Class 10 Maths Chapter 2, NCERT Solutions for Class 10 Maths Chapter 3, NCERT Solutions for Class 10 Maths Chapter 4, NCERT Solutions for Class 10 Maths Chapter 5, NCERT Solutions for Class 10 Maths Chapter 6, NCERT Solutions for Class 10 Maths Chapter 7, NCERT Solutions for Class 10 Maths Chapter 8, NCERT Solutions for Class 10 Maths Chapter 9, NCERT Solutions for Class 10 Maths Chapter 10, NCERT Solutions for Class 10 Maths Chapter 11, NCERT Solutions for Class 10 Maths Chapter 12, NCERT Solutions for Class 10 Maths Chapter 13, NCERT Solutions for Class 10 Maths Chapter 14, NCERT Solutions for Class 10 Maths Chapter 15, NCERT Solutions for Class 10 Science Chapter 1, NCERT Solutions for Class 10 Science Chapter 2, NCERT Solutions for Class 10 Science Chapter 3, NCERT Solutions for Class 10 Science Chapter 4, NCERT Solutions for Class 10 Science Chapter 5, NCERT Solutions for Class 10 Science Chapter 6, NCERT Solutions for Class 10 Science Chapter 7, NCERT Solutions for Class 10 Science Chapter 8, NCERT Solutions for Class 10 Science Chapter 9, NCERT Solutions for Class 10 Science Chapter 10, NCERT Solutions for Class 10 Science Chapter 11, NCERT Solutions for Class 10 Science Chapter 12, NCERT Solutions for Class 10 Science Chapter 13, NCERT Solutions for Class 10 Science Chapter 14, NCERT Solutions for Class 10 Science Chapter 15, NCERT Solutions for Class 10 Science Chapter 16, NCERT Solutions For Class 9 Social Science, NCERT Solutions For Class 9 Maths Chapter 1, NCERT Solutions For Class 9 Maths Chapter 2, NCERT Solutions For Class 9 Maths Chapter 3, NCERT Solutions For Class 9 Maths Chapter 4, NCERT Solutions For Class 9 Maths Chapter 5, NCERT Solutions For Class 9 Maths Chapter 6, NCERT Solutions For Class 9 Maths Chapter 7, NCERT Solutions For Class 9 Maths Chapter 8, NCERT Solutions For Class 9 Maths Chapter 9, NCERT Solutions For Class 9 Maths Chapter 10, NCERT Solutions For Class 9 Maths Chapter 11, NCERT Solutions For Class 9 Maths Chapter 12, NCERT Solutions For Class 9 Maths Chapter 13, NCERT Solutions For Class 9 Maths Chapter 14, NCERT Solutions For Class 9 Maths Chapter 15, NCERT Solutions for Class 9 Science Chapter 1, NCERT Solutions for Class 9 Science Chapter 2, NCERT Solutions for Class 9 Science Chapter 3, NCERT Solutions for Class 9 Science Chapter 4, NCERT Solutions for Class 9 Science Chapter 5, NCERT Solutions for Class 9 Science Chapter 6, NCERT Solutions for Class 9 Science Chapter 7, NCERT Solutions for Class 9 Science Chapter 8, NCERT Solutions for Class 9 Science Chapter 9, NCERT Solutions for Class 9 Science Chapter 10, NCERT Solutions for Class 9 Science Chapter 11, NCERT Solutions for Class 9 Science Chapter 12, NCERT Solutions for Class 9 Science Chapter 13, NCERT Solutions for Class 9 Science Chapter 14, NCERT Solutions for Class 9 Science Chapter 15, NCERT Solutions for Class 8 Social Science, NCERT Solutions for Class 7 Social Science, NCERT Solutions For Class 6 Social Science, CBSE Previous Year Question Papers Class 10, CBSE Previous Year Question Papers Class 12, JEE Main 2021 Question Paper Live Discussion, First, we take the solid sphere and slice it up into infinitesimally thin. 2 2 . 0 0 0 0 = Strategy. 3 CONCEPT: Moment of Inertia: Moment of inertia plays the same role in rotational motion as mass plays in linear motion. ] s Found inside – Page 33A ring of mass m and radius r is melted and then moulded into a sphere. The moment of inertia of the sphere will be (a) more than that of the ring (b) less than than of the ring (c) equal to that of the ring (d) None of these 38. In . 0 m = l = 1 y ] Lecture 1: Parallel Axis Theorem: Example 1. [ Moment of inertia , denoted by I , measures the extent to which an object resists rotational acceleration about a particular axis, and is the rotational analogue to mass. A uniform solid sphere has a moment of inertia / about an axis tangent to its surface. 314) Example: Hoop vs. 29.5 Moment of Inertia of a Sphere Course Home Syllabus About the Team; Readings Assignments Review: Vectors Lesson 0: Vectors [0.1 - 0.6] Week 1: Kinematics Week 1 Introduction . 2 ), Learn more at Get Started with MIT OpenCourseWare, MIT OpenCourseWare is an online publication of materials from over 2,500 MIT courses, freely sharing knowledge with learners and educators around the world. − ϕ Moment of Inertia of a Solid Sphere about its Diameter According to the figure a sphere of mass M and radius R is shown, whose density is p. We have to calculate the moment of inertia of the sphere about the diameter XX'. A typical point in this coordinate system is a distance from the origin. Found inside – Page 334TOPIC S MOMENTS OF INERTIA Many bodies in the Solar System are spherical , or approximately so , and spin about a diametrical axis . It is sometimes possible to estimate the moment of inertia of a body and this can give important ... + ) Therefore the volume of a sphere is zero. x Moment of inertia of a sphere can be explained in two parts (1) Solid Sphere (2 . {\displaystyle \left({\frac {r_{2}^{5}-r_{1}^{5}}{r_{2}^{3}-r_{1}^{3}}}\right)={\frac {5}{3}}r_{2}^{2}} = Inertia is the property of matter which resists change in its state of motion. Now we will use the Pythagoras theorem which gives us; Additionally, we have to find the density as well.
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